The wandering drunkard is the base problem for a LOT of Statistical Physics. Have a read https://medium.com/i-math/the-drunkards-walk-explained-48a0205d304 Essentially the mathematics of a "item" with a probability of stepping right (winning) or stepping left (losing), then repeating forever. So if we have a succession of bets lined up that we "know" the probability of winning (say 0.6) then what % of the betting pool should each bet be to maximise profit? If you bet 100% of the pool each time, very quickly you have no money at all. Conversely, if you bet 0.000001% of the pool each time, well your pool will barely change size. So for a given probability of winning, what is the best fractional bet for "the next step"? A numerical analysis solution (over a thousand simulated bets, starting with $100) yields if p=0.7 win fraction bet = 68% and above => $0 return over time Otimal bet fraction = 35% return (2x10^35) if ...